Flux Integral: How to find ds for line integrals in general

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Homework Help Overview

The discussion revolves around understanding the differential element ds in the context of line integrals, specifically within the framework of flux integrals. The subject area includes vector calculus and coordinate systems.

Discussion Character

  • Conceptual clarification, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants explore the derivation of ds, questioning its components in different coordinate systems. There is a focus on understanding the relationship between ds and the area elements in various contexts, such as Cartesian and polar coordinates.

Discussion Status

The discussion is active, with participants providing insights into the general procedure for determining ds based on the coordinate system used. Some guidance has been offered regarding the use of Jacobians in non-Cartesian coordinates, though no consensus has been reached on a singular method.

Contextual Notes

Participants express difficulty in determining ds for various problems, indicating a potential gap in understanding or application of the concept across different scenarios.

Marcin H
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Homework Statement


Screen Shot 2017-10-15 at 1.49.35 PM.png


Homework Equations


flux = int(b (dot) ds)

The Attempt at a Solution


I just wanted clarification on finding ds. I understand why ds is in the positive yhat direction (just do rhr) but I don't understand where the dxdz come from. How do we find ds in general?
 
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Marcin H said:
but I don't understand where the dxdz come from.
It s just the area of a rectangular element, dx by dz, in the xz plane. In polar it would have been rdrdθ, etc.
 
haruspex said:
It s just the area of a rectangular element, dx by dz, in the xz plane. In polar it would have been rdrdθ, etc.
So what is the general procedure for finding ds? I feel like I struggle determining ds for problems.
 
Marcin H said:
So what is the general procedure for finding ds? I feel like I struggle determining ds for problems.
It depends on your coordinate system. With general coordinates, ξ, η say, you consider the product dξdη. In general, the area enclosed by the points (ξ,η), (ξ+dξ,η), (ξ+dξ,η+dη), (ξ,η+dη) might have area equal to dξdη. To make the right area you may need to multiply by a Jacobian.

In the case of Cartesian coordinates dxdy does have the right area.
For plane polar coordinates you need a factor r. This works because the increments dr and rdθ are at right angles, so form a near-enough rectangle.
For the surface of a sphere in spherical polar a different Jacobian is needed.
 

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