I am trying to understand when exactly the voltage is reflected from secondary back to the primary. 1. The primary Switch turns ON, the primary inductor current ramps up 2. The primary switch turns OFF, current is induced in the secondary inductor-->diode conducts -->capacitor charges From flyback waveforms, when the switch goes off, the voltage at the primary is Vin+Reflected voltage (from secondary to primary). Ignore leakage inductance effect. The moment the primary switch goes off, secondary diode starts conducting and simultaneously secondary voltage is reflected on to the primary coil? Since the secondary side is not conducting when the primary switch is ON, there's no mag field in the coil. So no energy stored. But when the switch goes OFF, where does the secondary get it's energy from?