Focal Length of Lens: Solving for f with Object and Image Distances

AI Thread Summary
The problem involves calculating the focal length of a lens given the object distance (26.0 cm) and image distance (1.60 cm, negative due to the sign convention). The formula used is 1/f = 1/di + 1/do, leading to the equation 1/26 + 1/-1.6 = 1/f. The correct focal length is approximately -1.70 cm when rounded to three significant figures. Issues with computer acceptance of answers may arise from significant figure precision. The discussion highlights the importance of adhering to sign conventions and significant figures in optics calculations.
sp1974
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The homework problem is "An object 26.0 cm in front of a certain lens is imaged 1.60 cm in front of that lens (on the same side as the object). What is the focal length (in centimeters) of this lens"



1/f = 1/di + 1/do



I tried solving based on having distance of object (do) and distance of image (di) so 1/26 + 1/1.6 = 1/f and I solved for f coming up with 1.51 cm. I also tried with -1.6 since they are on the same side coming up with -1.71 and the computer doesn't accept either
 
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sp1974 said:
I tried solving based on having distance of object (do) and distance of image (di) so 1/26 + 1/1.6 = 1/f and I solved for f coming up with 1.51 cm. I also tried with -1.6 since they are on the same side coming up with -1.71 and the computer doesn't accept either
The image distance is negative (in the usual sign convention), so that is the correct approach.
 
so if I am understanding 1/26 + 1/-1.6 = 1/f and I should come up with -1.705 cm? It looks right but thinking the computer is being picky like my other answer
 
yeah its picky. I have put in 1.7, 1.71 1.705 and nothing. It does it everyonce in a while. I show teacher and all will be good. Thanks!
 
You might also try -1.70, that is the answer (-1.7049... cm) rounded to 3 sig figs.

Good luck!
 
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