Follow up for question i found on this forum please read

[atotheizzl09]

follow up for question i found on this forum! please read!

1. https://www.physicsforums.com/showthread.php?t=93375

above is a link to the problem



2. For part A, the force when x is at 6 meters is 4, and the mass is 0.20 kg, so you divide: (4 / 0.20) and get 20 as the acceleration of the particle when it's displacement x is at 6 meters?

For part B, would you use the equation v = v0 + (1/2atsquared) ?


For part C, i got the answer of 48 J when i multiplied 4x12.


For part D, would you use the equation v = dt?


For part E, i am not sure, but is the final speed zero?


For part F, change in momentum = mv(final) - mv(initial). i am just not sure of what to plug in for this one.


any help is greatly appreciated! thanks!

 

[member 553083]

For part A, yes, you have the correct calculation. For part B, yes, you would use the equation v = v0 + (1/2at^2). For part C, yes, that is correct. For part D, yes, you would use the equation v = d/t. For part E, yes, the final speed should be zero, as the particle has come to rest. For part F, you can calculate the change in momentum by plugging in the initial velocity (given in the problem) and the final velocity of 0 m/s. The formula would be mv(final) - mv(initial), where m is the mass of the particle and v is the velocity.