follow up for question i found on this forum!! please read!! 1. https://www.physicsforums.com/showthread.php?t=93375 above is a link to the problem 2. For part A, the force when x is at 6 meters is 4, and the mass is 0.20 kg, so you divide: (4 / 0.20) and get 20 as the acceleration of the particle when it's displacement x is at 6 meters? For part B, would you use the equation v = v0 + (1/2atsquared) ? For part C, i got the answer of 48 J when i multiplied 4x12. For part D, would you use the equation v = dt? For part E, i am not sure, but is the final speed zero? For part F, change in momentum = mv(final) - mv(initial). i am just not sure of what to plug in for this one. any help is greatly appreciated!! thanks!