Follow up for question i found on this forum please read

[atotheizzl09]

follow up for question i found on this forum! please read!

1. https://www.physicsforums.com/showthread.php?t=93375

above is a link to the problem



2. For part A, the force when x is at 6 meters is 4, and the mass is 0.20 kg, so you divide: (4 / 0.20) and get 20 as the acceleration of the particle when it's displacement x is at 6 meters?

For part B, would you use the equation v = v0 + (1/2atsquared) ?


For part C, i got the answer of 48 J when i multiplied 4x12.


For part D, would you use the equation v = dt?


For part E, i am not sure, but is the final speed zero?


For part F, change in momentum = mv(final) - mv(initial). i am just not sure of what to plug in for this one.


any help is greatly appreciated! thanks!

 

[Nate810]

For part A, yes, you have the correct calculation. For part B, yes, you would use the equation v = v0 + (1/2at^2). For part C, yes, that is correct. For part D, yes, you would use the equation v = d/t. For part E, yes, the final speed should be zero, as the particle has come to rest. For part F, you can calculate the change in momentum by plugging in the initial velocity (given in the problem) and the final velocity of 0 m/s. The formula would be mv(final) - mv(initial), where m is the mass of the particle and v is the velocity.

 

[ogb p]

I would first like to commend you for seeking help and clarification on this forum. It shows your dedication to understanding the problem and finding the correct solution.

For part A, your calculation and answer of 20 m/s^2 for the acceleration at x = 6 meters is correct. This can also be verified by using the formula F = ma, where F is the force (4 N) and m is the mass (0.20 kg), and solving for a.

For part B, yes, you can use the equation v = v0 + (1/2)at^2 to calculate the final velocity at any given time. Just make sure to use the correct values for initial velocity (v0) and time (t).

For part C, your answer of 48 J for the work done is also correct. This can be calculated by using the formula W = Fd, where W is work, F is force, and d is displacement.

For part D, the correct equation to use is v = at. This will give you the final velocity at any given time, t.

For part E, the final speed will indeed be zero at the point where the particle reaches its maximum displacement (x = 12 meters). This is because the particle has come to a stop and has no more velocity.

For part F, your formula for change in momentum is correct. Just make sure to use the correct values for final and initial momentum (mv) at the given points.

I hope this helps clarify the problem for you. Keep up the good work and don't hesitate to seek assistance when needed. As a scientist, it is important to constantly seek knowledge and understanding. Good luck!