For those who have this textbook.

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SUMMARY

The discussion revolves around the omission of friction forces in the solutions to problem 55 from "Physics for Scientists and Engineers Volume 1 Eighth Edition" by Serway and Jewett. Participants clarify that friction is often disregarded in physics problems to simplify the concepts being taught. The correct interpretation of the coefficients of kinetic friction is highlighted, with the notation μ1 and μ2 being confirmed as the proper labels in the textbook. The confusion stems from the initial misinterpretation of these coefficients as m1 and m2.

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  • Understanding of Newton's Second Law (F = ma)
  • Familiarity with the concept of friction in physics
  • Knowledge of basic physics problem-solving techniques
  • Access to "Physics for Scientists and Engineers Volume 1 Eighth Edition" by Serway and Jewett
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  • Review the role of friction in classical mechanics problems
  • Study the implications of ignoring friction in physics equations
  • Examine additional examples from "Physics for Scientists and Engineers" that involve friction
  • Learn about the significance of coefficients of friction in real-world applications
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Students studying physics, educators teaching mechanics, and anyone seeking to understand the simplifications made in physics problems involving friction.

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Homework Statement



In Physics for Scientists and Engineers Volume 1 Eighth Edition (Serway, Jewett)

Number 55. in Chapter 5, I checked the answer key and would like to know why they don't consider the forces of friction in a), b), c), d), and e)? This confuses me. Thank you.

Homework Equations



F = ma

The Attempt at a Solution



The solutions for f and g I got right.
 
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I don't have the book, what is the actual question?

Many times friction is ignored in order to explain concepts with simplicity.
 
QuarkCharmer said:
I don't have the book, what is the actual question?

Many times friction is ignored in order to explain concepts with simplicity.

I found it online:

http://www.cramster.com/answers-sep-10/physics/blocks-masses-m1-m2-nbsptwo-blocks-masses-m1-m2-table_950775.aspx

The answer key gives:

b) F, c) F - P, d) P, e) m1: F - P = m1a; m2: P = m2a

I want to add that obviously in the book the coefficients are labeled "mu"1 and 2
 
Last edited by a moderator:
DannyPhysika said:
Number 55. in Chapter 5, I checked the answer key and would like to know why they don't consider the forces of friction in a), b), c), d), and e)? This confuses me.
Seems just wrong to me.

Does the book really say: "The coefficient of kinetic friction between the block of mass m1 and the table is m1, and that between the block of mass m2 and the table is m2." That makes no sense! (Maybe μ1 and μ2?)
 
DannyPhysika said:
I want to add that obviously in the book the coefficients are labeled "mu"1 and 2
That's better.
 
Doc Al said:
Seems just wrong to me.

Does the book really say: "The coefficient of kinetic friction between the block of mass m1 and the table is m1, and that between the block of mass m2 and the table is m2." That makes no sense! (Maybe μ1 and μ2?)

Yeah it's actually labeled μ in the book
 

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