- #1
nonaa
- 17
- 0
For what values of M does this integral converge?
[tex]\int_{-\infty}^{0}\frac{x.e^x}{(1-e^{2x})^M}dx[/tex]
My pathetic attempt for solution ended here:
[tex]\frac{2x.e^x}{2.(-1)^M(e^{2x}-1)^M}.x^{M-1}\stackrel{x\rightarrow0}{\longrightarrow}\frac{(-1)^M}{2}[/tex]
[tex]M-1<1, M<2[/tex]
Am I going in the right direction? And what to do if [tex]x\rightarrow\infty[/tex]?
[tex]\int_{-\infty}^{0}\frac{x.e^x}{(1-e^{2x})^M}dx[/tex]
My pathetic attempt for solution ended here:
[tex]\frac{2x.e^x}{2.(-1)^M(e^{2x}-1)^M}.x^{M-1}\stackrel{x\rightarrow0}{\longrightarrow}\frac{(-1)^M}{2}[/tex]
[tex]M-1<1, M<2[/tex]
Am I going in the right direction? And what to do if [tex]x\rightarrow\infty[/tex]?