For what values of M does this integral converge?

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The integral \int_{-\infty}^{0}\frac{x.e^x}{(1-e^{2x})^M}dx converges for specific values of M. The analysis indicates that for convergence, M must satisfy the condition M < 2. The discussion highlights the importance of understanding the behavior of the integral as x approaches both 0 and negative infinity, emphasizing that the integral must remain finite across its entire range.

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nonaa
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For what values of M does this integral converge?

[tex]\int_{-\infty}^{0}\frac{x.e^x}{(1-e^{2x})^M}dx[/tex]


My pathetic attempt for solution ended here:

[tex]\frac{2x.e^x}{2.(-1)^M(e^{2x}-1)^M}.x^{M-1}\stackrel{x\rightarrow0}{\longrightarrow}\frac{(-1)^M}{2}[/tex]

[tex]M-1<1, M<2[/tex]

Am I going in the right direction? And what to do if [tex]x\rightarrow\infty[/tex]?
 
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Hi nonaa! Welcome to PF! :smile:

No, you're misreading the question.

It means for what values of M is the whole integral finite. :wink:
 


Hi, I'm here for almost a day but you people are so nice and helpful :) I'm glad I've found this forum :)

And how to do this? I've never solved such type of problems before. Would you give me a little hint?
 

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