For what values of p does this series converge?

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Homework Statement


Find all values of p for which the given series converges absolutely: \sum from k=2 to infinity of [1/((logk)^p)].


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The Attempt at a Solution


I've tried the ratio test, the root test, limit comparison test ... everything. I know the answer is the null set (that is, for no values of p does the series converge), but I can't prove that rigorously.
 
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Do a comparison test with 1/k. Can you show lim k->infinity (log(k))^p/k=0?
 
have you considered simply looking at this question as a "p-test"
 
oinkbanana said:
have you considered simply looking at this question as a "p-test"
The series is not a p-series, so this test is not applicable. Here is a p-series:
\sum_{n = 1}^{\infty} \frac{1}{n^p}
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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