Force of kinesin molecule within cells

Click For Summary
SUMMARY

The discussion focuses on calculating the force exerted by a kinesin molecule to accelerate an organelle with a mass of 0.028 picograms (pg) from rest to a velocity of 2.8 micrometers per second (μm/s) over a time span of 45 microseconds (μs). The relevant equation used is ft=mv, where 'f' represents force, 't' is time, 'm' is mass, and 'v' is velocity. The initial calculations provided by the user were incorrect, specifically in the application of the equation and unit conversions.

PREREQUISITES
  • Understanding of Newton's second law of motion
  • Familiarity with unit conversions (e.g., micro to standard units)
  • Basic knowledge of kinesin molecular motors
  • Proficiency in manipulating scientific notation
NEXT STEPS
  • Review calculations involving force and acceleration using Newton's laws
  • Study the mechanics of kinesin transport in cellular biology
  • Learn about unit conversion techniques in physics
  • Explore the role of microtubules in intracellular transport
USEFUL FOR

Students studying cellular biology, biophysics researchers, and anyone interested in the mechanics of molecular motors such as kinesins.

omc1
Messages
100
Reaction score
0

Homework Statement

Within cells, small organelles containing newly synthesized proteins are transported along microtubules by tiny molecular motors called kinesins. What force does a kinesin molecule need to deliver in order to accelerate an organelle having mass 0.028 pg from rest to 2.8 microm/s over a time of 45.0 micros?

Homework Equations

ft=mv



The Attempt at a Solution

i converted the micro to m and s, 2.8x10^-6 m/s and 2.8x10^-17 kg and 4.5x10^-5 s. for my answer i got 1.87x10^-18m/s but its wrong...thanks for help!
 
Physics news on Phys.org
The conversions look OK. I suppose you made a mistake in your calculations.