Force on a point charge due to a sphere

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Homework Help Overview

The problem involves calculating the force exerted by an insulated conducting sphere on a point charge in its electric field. The scenario includes a conducting sphere with a total charge and a point charge of the same sign, with the condition that the point charge is much smaller than the sphere's charge.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the use of Legendre solutions to Laplace's equation and boundary conditions to derive the electric potential and field of the sphere. Questions arise about the assumptions regarding charge distribution and the relevance of angular dependence in the electric field. Some participants consider whether an image charge method might be more appropriate for the problem.

Discussion Status

The discussion is ongoing, with participants exploring different methods to approach the problem. There is no explicit consensus on the best method, but suggestions for alternative approaches, such as the image method, have been made.

Contextual Notes

Participants note the complexity of deriving constants from boundary conditions and the implications of charge distribution on the conducting sphere. There is an acknowledgment of the limitations of the chosen method and the potential need for additional techniques.

andre220
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Homework Statement


An insulated conducting sphere of radius ##R##, carrying a total charge of ##Q##, is in the field of a point charge ##q## of the same sign. Assume ##q\ll Q##. Calculate and plot the force exerted by the sphere on ##q## as a function of distance from the center. In particular, for ##q/Q = 0.1##, calculate the point at which the direction of force reverses.

Homework Equations


The electric field due a point charge $$E_\mathrm{pt} = \frac{q}{4\pi\epsilon_0 r^2}$$
$$\Phi(r,\theta) = \sum\limits_{l=0}^\infty \left(A_l r^l + \frac{B_l}{r^{l+1}}\right) P_l\left(\cos{\theta}\right)$$
$$\vec{E} = -\vec{\nabla}\Phi$$

The Attempt at a Solution


So since the solution is wanted as a function of distance from the center of the sphere, I am using the legendre solutions to laplace's equation. The boundary conditions are ##\Phi(R,\theta) = 0## and ##E_\mathrm{in} -E_\mathrm{out} = -\sigma/\epsilon_0 \implies E_\mathrm{point} - \nabla_r \Phi =-\frac{4\pi R^2}{\epsilon_0}##
Then once the boundary conditions are satisfied then the force is just ##F = qE_\mathrm{sphere}##.

So for the potential of the sphere:
$$\Phi(r) = A_0 + \frac{B_0}{r}$$
$$\Phi(R) = 0 = A_0 + \frac{B_0}{R}\implies B_0 = -A_0 R\implies \Phi(r) = A_0\left(1-\frac{R}{r}\right)$$
$$E_\mathrm{sphere} = -\frac{2 A_0 R}{r^2}$$
Then, applying the boundary conditions at the surface of the sphere:
$$\frac{q}{4\pi\epsilon_0 R^2} + \frac{2 A_0}{R} = -\frac{4\pi R^2 Q}{\epsilon_0}\implies A_0 = \frac{-q + 16\pi^2 R^4 Q}{8\pi\epsilon_0 R}$$

Then,
$$E_\mathrm{sphere} = \frac{1}{r^2}\left(\frac{q + 16\pi^2 Q R^4}{4\pi\epsilon_0}\right)$$
Then from here I would just do force by multiplying by ##q## of the point charge and then find the point at which the force reverses.

a lot to take in, but does this seem correct thus far?
 
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andre220 said:
So for the potential of the sphere:
$$\Phi(r) = A_0 + \frac{B_0}{r}$$
Where does that come from? I think the idea of the conducting sphere is the non-uniform charge distribution. The electric field and therefore the potential should depend on θ.
 
Right, then I don't see how I can get the constants ##A_1, B_1## with only two boundary conditions.
Thats why I only chose to keep ##l = 0## terms.
 
There are formulas how a charge q at some distance L will influence charges on a conducting sphere. It's possible to derive them but I guess that is not necessary here.
Q does not matter for this induced charge.
 
Is this method correct that I am using? Or should I use an image method here?
 
Your method is not incorrect, but it involves an infinite series. I would try the image method first.
 

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