Force on current carrying conductor

AI Thread Summary
To find the force on a 20cm wire carrying 10A in a 0.3T magnetic field at a 40-degree angle, the formula F=LIB sin(θ) is used. The calculated force is 0.35N, while the textbook states it is 0.39N. A participant suggests that the discrepancy may be due to a calculation error, particularly in the sine value used. They confirm that sin(40) is approximately 0.643, which could affect the final result. The discussion highlights the importance of careful calculation in physics problems.
uzair_ha91
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Homework Statement



A 20cm wire carrying a current of 10A is placed in a uniform
magnetic field of 0.3T. If the wire makes an angle of 40 degrees with
the direction of magnetic field, find the force acting on the wire.


Homework Equations



F=LIB sin<theta>

The Attempt at a Solution



I got the answer:: 0.35, but in the textbook, the answer written at the back is 0.39...which one's correct??
 
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uzair_ha91 said:

Homework Statement



A 20cm wire carrying a current of 10A is placed in a uniform
magnetic field of 0.3T. If the wire makes an angle of 40 degrees with
the direction of magnetic field, find the force acting on the wire.


Homework Equations



F=LIB sin<theta>

The Attempt at a Solution



I got the answer:: 0.35, but in the textbook, the answer written at the back is 0.39...which one's correct??

Rounding my answer down I agree with the book.I bet you punched the wrong calculator button when you was working out the sin.Sin40=0.643
 
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