Force On Object With Constant Speed

ptguard1
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A sack of flour of mass 6.00 kg is lifted vertically at a constant speed of 4.00 m/s through a height of 18.0 m

How great a force is required?

F=ma


I found the force that the sack has on the Earth (58.8N), but don't understand how I am suppose to find what force is being applied to the sack in order to give it a constant speed of 4.00 m/s.
 
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I figured out that the force is equal to the 58.8 N of force that the sack had on the earth. My logic was that an object can be lifted at different speeds with the same force, is this true or only partially true?
 
As long as the speed of the object is constant the total forces on the object should add up to 0. Since the gravitational field is pretty much constant at the altitude differences you have in your problem you just need to add the same force as the gravitational force.
 
Hi, I had an exam and I completely messed up a problem. Especially one part which was necessary for the rest of the problem. Basically, I have a wormhole metric: $$(ds)^2 = -(dt)^2 + (dr)^2 + (r^2 + b^2)( (d\theta)^2 + sin^2 \theta (d\phi)^2 )$$ Where ##b=1## with an orbit only in the equatorial plane. We also know from the question that the orbit must satisfy this relationship: $$\varepsilon = \frac{1}{2} (\frac{dr}{d\tau})^2 + V_{eff}(r)$$ Ultimately, I was tasked to find the initial...
The value of H equals ## 10^{3}## in natural units, According to : https://en.wikipedia.org/wiki/Natural_units, ## t \sim 10^{-21} sec = 10^{21} Hz ##, and since ## \text{GeV} \sim 10^{24} \text{Hz } ##, ## GeV \sim 10^{24} \times 10^{-21} = 10^3 ## in natural units. So is this conversion correct? Also in the above formula, can I convert H to that natural units , since it’s a constant, while keeping k in Hz ?
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