Force On Object With Constant Speed

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SUMMARY

The discussion centers on calculating the force required to lift a 6.00 kg sack of flour at a constant speed of 4.00 m/s through a height of 18.0 m. The force of gravity acting on the sack is determined to be 58.8 N, which is equal to the weight of the sack (mass multiplied by gravitational acceleration). To maintain a constant speed, the applied force must equal the gravitational force, resulting in a net force of zero. Therefore, the force required to lift the sack at a constant speed is also 58.8 N.

PREREQUISITES
  • Understanding of Newton's Second Law (F=ma)
  • Basic knowledge of gravitational force calculations
  • Familiarity with the concept of constant velocity
  • Knowledge of mass and weight relationships
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  • Study the implications of Newton's First Law regarding constant velocity
  • Explore the concept of net force and equilibrium in physics
  • Learn about different forces acting on objects in motion
  • Investigate real-world applications of lifting forces in engineering
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ptguard1
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A sack of flour of mass 6.00 kg is lifted vertically at a constant speed of 4.00 m/s through a height of 18.0 m

How great a force is required?

F=ma


I found the force that the sack has on the Earth (58.8N), but don't understand how I am suppose to find what force is being applied to the sack in order to give it a constant speed of 4.00 m/s.
 
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I figured out that the force is equal to the 58.8 N of force that the sack had on the earth. My logic was that an object can be lifted at different speeds with the same force, is this true or only partially true?
 
As long as the speed of the object is constant the total forces on the object should add up to 0. Since the gravitational field is pretty much constant at the altitude differences you have in your problem you just need to add the same force as the gravitational force.
 

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