Calculate Force on 10m x 12m Roof in Kansas

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AI Thread Summary
The discussion revolves around calculating the force exerted on a 10m x 12m roof in Kansas due to high wind speeds. The problem highlights the impact of wind at 27.5m/s, which creates a pressure difference that could potentially lift the roof. Initial confusion arose regarding the application of relevant equations for pressure and force, particularly in determining the pressures inside and outside the house. After some contemplation and a break, the individual realized the solution was simpler than initially thought. Ultimately, the problem emphasizes the importance of understanding atmospheric pressure dynamics in structural integrity during high winds.
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Homework Statement


Dorothy is up on her 10.0m by 12.0m roof enjoying the view of Kansas. Suddenly, a strong wind blows down her ladder, leaving her stranded. She knows that a high wind reduces the air pressure on the roof, and that there is a danger that the atmospheric pressure inside the house will blow the roof off. As the wind reaches a speed of 27.5m/s, she calls to her Auntie Em for help. Calculate the force on the roof.


Homework Equations


p1A1v1=p2A2v2
P2 + (.5)p(v2^2)=P1 + (.5)p(v1^2)
P=F/A

The Attempt at a Solution


I have been looking at this problem for awhile now and I'm not to sure on where to start. I know you can find the area of the roof by multiplying the values. Getting you a 120 m^2. I thought maybe you could use the second equation I listed. And since the velocity in the house is 0 you could set P1 = P2 + .5(v2^2)p but I don't know how to find P1 or P2... So I guess I'm just kinda at a loss. Can someone push me in the right direction.
 
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Sorry for the question everyone. I figured out the answer. I was overcomplicating the problem and it was just stressing me out but I took a break and came back and realized it wasn't hard at all.
 
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