Forced response and Laplace transform

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Homework Help Overview

The discussion revolves around solving a second-order linear differential equation using the Laplace transform technique. The equation presented is d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)), which requires finding the forced response.

Discussion Character

  • Mixed

Approaches and Questions Raised

  • Participants discuss the conversion of terms from the time domain to the Laplace domain, expressing confusion about the correct application of initial conditions and the transformation of the right-hand side of the equation.

Discussion Status

There is an ongoing exploration of the correct application of the Laplace transform, with some participants questioning the assumptions regarding initial conditions and the transformations used. Clarifications are being sought regarding the presence of variables in the transformed equation.

Contextual Notes

Participants note the importance of initial conditions and the potential impact of these on the transformation process. There is also mention of confusion regarding the correct form of the right-hand side of the equation after applying the Laplace transform.

4real4sure
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Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:
 
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4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:

Unless you have a couple of 0 initial conditions, you need to put them in the transforms of the derivatives. You also need to transform the right side of the DE. Solve the resulting equation for Y(s) and invert it.
 
I found out by applying laplace to each factor,

s^2y(t)+4sy(t)+4y(t)=-7t(t+3)
s^2y(t)+4sy(t)+4y(t)=-7t(t)-7y(3)
y(t)(s^2+4s+11)=y(3)

But from here, I am confused. Since in the question the value of u(t) was given to be e^-3t. Other wise I would have used laplace transform of u(t) which is 1/s.
Also in the last line, I couldn't factorize the polynomial which is hindering my progress.
Any help would be whole heartedly appreciated.
 
4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)).

LCKurtz said:
Unless you have a couple of 0 initial conditions, you need to put them in the transforms of the derivatives. You also need to transform the right side of the DE. Solve the resulting equation for Y(s) and invert it.

4real4sure said:
I found out by applying laplace to each factor,

s^2y(t)+4sy(t)+4y(t)=-7t(t+3)

Did you read my reply? Are your initial conditions y(0)=0 and y'(0) = 0 or not? You were using Y(s) for the transform of y(t). You have t's in your transform when they should be s's and y when you should have Y. And where did the t(t+3) on the right side come from? It surely isn't the transform of e^(-3t).
 
4real4sure said:

Homework Statement


d'^2 (y)/dt + 4 (dy/dt) + 4y = -7(e^(-3t)). Here I need to forced response of this differential equation using laplace transform technique.


Homework Equations




The Attempt at a Solution


I understand the part of converting each term to each laplace,
d^2y/dt to Y(s)*s^2, dy/dt to Y(s)*s, y(t) to Y(s), where each term is being converted from f(t) to F(s). I really confused on how to proceed with this question form here :cry:

L[y'(t)](s) ≠ s*Y(s) and L[y"(t)](s) ≠ s^2*Y(s) in general (although for some special conditions on y(.) these are true). Check your sources!

RGV
 

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