Forces in Truss Members (Statics)

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Homework Help Overview

The discussion revolves around analyzing forces in truss members, specifically focusing on a problem involving a pinned connection at point A and a roller connection at point B. The original poster mentions the need to find reaction forces and expresses difficulty due to missing dimensions in the problem statement.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss methods for finding reaction forces, including using moments and the sum of forces. There is a focus on the geometry of the truss, particularly the dimensions related to equilateral triangles and the perpendicular distance from the applied load to point A.

Discussion Status

Participants are exploring various interpretations of the geometry involved in the problem. Some have offered insights into the calculations of distances, while others question the correctness of these interpretations. The discussion remains open with no explicit consensus reached.

Contextual Notes

The original poster notes that dimensions are not provided in the problem, which is a significant constraint affecting the analysis. There are also indications of varying interpretations regarding the distances and forces involved.

cpmustang07
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Homework Statement



See attachment.
Edit: Point A is a pinned connection (has a reactionary force in X and Y direction). Point B is a roller connection (only has reactionary force in Y direction)

Homework Equations



Sum Fx=0
Sum Fy=0
Sum of Moments=0


The Attempt at a Solution




Find reaction forces at point A and D. Normally this wouldn't be an issue. I'd just find the reaction force of D by solving for the moment around point A. Then find A by knowing that the sum of forces in Y direction is 0. However, dimensions are not given in the problem. I have the answers, but I do not see how to get to them.

After finding reaction forces, isolate each joint and begin with joint with no more than two unknowns. Proceed until all forces are found.
 

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These are all equilateral triangles...each horizontal member has the same length, L. What would be the perp. distance from the applied load to A?
 
PhanthomJay said:
These are all equilateral triangles...each horizontal member has the same length, L. What would be the perp. distance from the applied load to A?

3*cos(60)*L, correct?
 
cpmustang07 said:
3*cos(60)*L, correct?
Interesting way to say 1.5L, which is correct.
 
SammyS said:
Interesting way to say 1.5L, which is correct.

No...
 
Phrak said:
No...
Why not?? If the length of each horizontal member is L, the perpendicular distance from the line of action of the applied load to A is 1.5 L.
 
PhanthomJay said:
Why not?? If the length of each horizontal member is L, the perpendicular distance from the line of action of the applied load to A is 1.5 L.

right. 1.5L to A and 1.5KN on D.
 
Thank you for your help guys. I'll work on it again today and see if this different train of thought will get me through it. :)

I got it guys. Thank you. Apparently I'm really slow. ;)
 
Last edited:

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