Forces on a Solid Disk: Determining F3

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The discussion revolves around calculating the magnitude of force F3 acting on a solid disk subjected to two other forces, F1 and F2. Given the mass and radius of the disk, along with its rotational motion over a specified time, participants are trying to derive the value of F3. The moment of inertia formula is provided as a key equation for the calculations. One participant mentions arriving at an answer of 96.72 Newtons but expresses confusion about the process used to reach that conclusion. Clarification and guidance on the calculations are sought to assist in solving the problem.
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Homework Statement



Three forces of F1, F2, and F3 are applied to a solid disk with a mass of 3.6 kg and radius of 2.9 meters. F1 is directly above the center of the disk with a magnitude of 47 Newtons directed in the positive x direction, F2 is directly to the right of the center and has a magnitude of 47 Newtons directed in the negative y direction, and F3 is directly to the left of the center and is also directed in the negative y direction. If the disk is initially at rest and then rotates about its center 7 rotations counter-clockwise (positive direction) in a time of 13 seconds, what is the magnitude of F3 in Newtons?

Homework Equations



The moment of inertia for the disk about its center is I = 1/2 M R2.

The Attempt at a Solution



Answer comes to be 96.72. I have no idea how to get that answer
 
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Hi Paulie! :wink:

Show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 

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