# Forces on pin Did the problem but cant check answer

• frozenguy
In summary, Frozenguy calculated the force supported by the slip joint pliers using the book's equation and broke it down into its component forces. However, he ran into an issue where the angle of the member and the vector components differed, preventing him from getting the correct answer. He was able to solve the problem by drawing the triangle of forces on a free body diagram.

## Homework Statement

We are supposed to compute the force supported by pin at A for the slip joint pliers.
The book says they are under a 30# grip.
I summed forces about A to find B, then broke B up into components by dividing by $$\sqrt{2}$$ and then I summed forces for Ax and Ay and found A.

Let me know if you can't read part of my handwriting.

frozenguy: That is currently incorrect. You used B in your calculation without showing the corresponding B vector on your free-body diagram. Did you try a summation of forces or moments on your answers, to see if they are in equilibrium? Keep trying.

Also, generally always maintain four significant digits throughout all your intermediate calculations, then round only the final answer to three significant digits, unless the first significant digit of the final answer is 1, in which case round the final answer to four significant digits.

Now I'm getting kind of confused. If I take moments around B, A should be able to balance out the 30lb moment. So shouldn't A balance out the 30 moment by it self? Thats what I don't get, because if I then take moments about A, B has to balance 30 all by itself. But in the real world, moments aren't dependent on which one you look at, what am I missing here?

You can take moments about any point you wish; therefore, taking moments about point A is fine. Show vector B in your free-body diagram for your moment summation equation about point A.

So then B is 135lb at 45 deg above positive x axis.. So if I sum moments around C, I can find A?

I recommend you draw to scale the triangle of forces on this free body diagram. That should uncover your error.

frozenguy: Why do you think force vector B is parallel to the jaw?

nvn said:
frozenguy: Why do you think force vector B is parallel to the jaw?

Because of the direction of the component forces, but looking at the picture, intuition says that b's force vector should be the other direction, perpendicular to the face of the jaw ya?

Oh, in my summation of Fx at the end, those are supposed to be Ax's

frozenguy: That is correct; force vector B should be perpendicular to the jaw.

I'm not confident about my answer because of how I obtained B. While doing one problem in my book that had the answer displayed, I couldn't do what I did in this problem to get the magnitude of the vector. It like, had nothing to do with the angle of the member. The angle of the member was different then the angle the vector components gave me.

Try it again, and we'll see if you get the right answer this time.

I'm feeling pretty confident about that.

## 1. What is the concept of "forces on pin"?

The concept of "forces on pin" refers to the physical forces that act upon a pin or any other object that is connected to a fixed point. These forces can include tension, compression, shear, and bending forces, depending on the specific situation.

## 2. How do you calculate the forces on a pin?

To calculate the forces on a pin, you need to first identify all the external forces acting on the pin, such as weight, applied forces, and reaction forces. Then, you can use principles of static equilibrium and free body diagrams to determine the magnitude and direction of each force.

## 3. What factors affect the forces on a pin?

The forces on a pin can be affected by various factors, including the weight and shape of the object connected to the pin, the angle and direction of applied forces, and the material and dimensions of the pin itself. Other factors may also come into play depending on the specific situation.

## 4. How do you know if the forces on a pin are in equilibrium?

If the forces on a pin are in equilibrium, it means that the sum of all forces acting on the pin is equal to zero. This indicates that the pin is not moving or rotating, and the forces are balanced. To check for equilibrium, you can use the equations of static equilibrium or draw a free body diagram and ensure that all forces cancel out.

## 5. Can you provide an example of forces on a pin in real life?

An example of forces on a pin in real life can be seen in a simple seesaw. The pin connecting the seesaw to its support acts as a pivot point, and the forces of weight and applied force on each end of the seesaw act on this pin. By understanding and analyzing the forces on the pin, we can determine if the seesaw will be in balance or if one end will tip down.