Forces on pin Did the problem but cant check answer

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Discussion Overview

The discussion revolves around calculating the force supported by a pin in slip joint pliers under a specified grip force. Participants are exploring the mechanics involved, including the summation of forces and moments, and the correct representation of force vectors in free-body diagrams.

Discussion Character

  • Homework-related
  • Technical explanation
  • Debate/contested

Main Points Raised

  • One participant describes their approach to calculating the force at pin A, mentioning the grip force and the use of components to find the resultant force.
  • Another participant challenges the correctness of the initial calculations, suggesting the need for a proper free-body diagram and equilibrium checks.
  • A participant expresses confusion about the relationship between moments around different points and how they should balance each other.
  • There is a suggestion to draw the triangle of forces to identify potential errors in the calculations.
  • Participants discuss the direction of force vector B, with some indicating it should be perpendicular to the jaw of the pliers.
  • One participant expresses uncertainty about their numerical answer, linking it to difficulties in determining the magnitude of vector B based on different angles.

Areas of Agreement / Disagreement

Participants do not reach a consensus on the correctness of the calculations, as there are multiple viewpoints regarding the representation of forces and moments. Some participants agree on the need for proper vector representation, while others remain uncertain about their numerical results.

Contextual Notes

There are unresolved questions regarding the assumptions made in the calculations, particularly about the angles and directions of force vectors. The discussion highlights the complexity of analyzing forces in a mechanical system.

frozenguy
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Homework Statement


470.jpg


We are supposed to compute the force supported by pin at A for the slip joint pliers.
The book says they are under a 30# grip.
I summed forces about A to find B, then broke B up into components by dividing by \sqrt{2} and then I summed forces for Ax and Ay and found A.

Let me know if you can't read part of my handwriting.

Thanks in advance!
 
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frozenguy: That is currently incorrect. You used B in your calculation without showing the corresponding B vector on your free-body diagram. Did you try a summation of forces or moments on your answers, to see if they are in equilibrium? Keep trying.

Also, generally always maintain four significant digits throughout all your intermediate calculations, then round only the final answer to three significant digits, unless the first significant digit of the final answer is 1, in which case round the final answer to four significant digits.
 
Now I'm getting kind of confused. If I take moments around B, A should be able to balance out the 30lb moment. So shouldn't A balance out the 30 moment by it self? Thats what I don't get, because if I then take moments about A, B has to balance 30 all by itself. But in the real world, moments aren't dependent on which one you look at, what am I missing here?
 
You can take moments about any point you wish; therefore, taking moments about point A is fine. Show vector B in your free-body diagram for your moment summation equation about point A.
 
So then B is 135lb at 45 deg above positive x axis.. So if I sum moments around C, I can find A?
 
I recommend you draw to scale the triangle of forces on this free body diagram. That should uncover your error.
 
frozenguy: Why do you think force vector B is parallel to the jaw?
 
nvn said:
frozenguy: Why do you think force vector B is parallel to the jaw?

Because of the direction of the component forces, but looking at the picture, intuition says that b's force vector should be the other direction, perpendicular to the face of the jaw ya?


Oh, in my summation of Fx at the end, those are supposed to be Ax's
 
frozenguy: That is correct; force vector B should be perpendicular to the jaw.
 
  • #10
So was that my only problem? lol, its sad I'm not confident about my numerical answer.

I'm not confident about my answer because of how I obtained B. While doing one problem in my book that had the answer displayed, I couldn't do what I did in this problem to get the magnitude of the vector. It like, had nothing to do with the angle of the member. The angle of the member was different then the angle the vector components gave me.
 
  • #11
Try it again, and we'll see if you get the right answer this time.
 
  • #12
How about this

statics2.jpg


I'm feeling pretty confident about that.
 
  • #13
Nice work, frozenguy. Your answer is correct.
 

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