Hello! This is my first post so please forgive me if I'm doing this wrong. Thanks! http://img4.imageshack.us/img4/3922/godfdb.jpg [Broken] Ok it has always stumbled me why we use the angle the ramp makes with the surface it rests on when resolve gravity into it's components I understand why and how to resolve vectors into it's components the force of gravity, x component = mg sin theta the force of gravity, y component = mg cos theta the force of gravity is clearly the hypotenuse of the triangle the force of gravity, the x component, is clearly the opposite side of the triangle the force of gravity, the y component, is clearly the adjacent side of the triangle ok but it's very clear that the angle the ramp makes with the surface that it sits on is not the anlge being used in those formulas... So I've tried to find the anlge that I belive is being used. I drew the triangle (in a dark red) in the diagram above with the angle that I belive is the angle that is being used in those formulas. Ok I have always been told that you can use the angle the ramp makes with the surface it sits on. This lead me to belive that the two angles (indicated in the diagram I drew) are equal to each other... Ok, how do I prove that these angles are equal to each other? It has been a while sense I have taken geometry so my skills are a little bit rusy in proofs. I always remeber doing them in statement reason format and we would make a table... Please tell me step by step because I'm a little bit rusty in geometry it's been a while, just telling me that the angles are complementary won't help because I have forgten how to prove two different angels are complementary in different tirangles when the triangles are seperate. I do remeber what complementary means. So if you could please give both the statements and reasons for why the statements are true that would be great... =] also it seems a little bit odd to me drawing the x component of the force of gravity down there to complete the triangle (the red one) because it's no longer sitting on the x axis... If we place it down there don't we also have to place the x axis down there? I've always been told to put the x axis through the center of the object and parrallel to the ramp that way when you do problems like trying to find how far it'll fall down you would have to do less work... so it just seems a bit odd removing from the x component from the x axis and placing it randomly on the diagram to complete a triangle... Thanks so much!!!