Form 8 Digit Number with 7s, 6s & 0s

  • Thread starter Thread starter harishm18
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The discussion revolves around forming an 8-digit number based on specific conditions related to the frequency of each digit. The ones place represents the count of 7's in the number, the tens place indicates the count of 6's, and this pattern continues up to the ten million place, which represents the count of 0's. Participants express confusion over the phrasing of the riddle, particularly the use of "no" to mean both "number" and "no." There are also comments on the number of digits, with one participant pointing out that the number only has 6 digits, suggesting a miscount. The conversation includes light-hearted remarks about the complexity of the riddle and its wording.
harishm18
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main aim : You have to form a 8 digit number such that
the conditions are
the ones place stands no of 7's in the final 8 digit no that will form
the tens place stands : no of 6's in the final 8 digit no
...
...
...
then the 10^7 the place stands for no of 0's in the 8 digit no



what is the no.?
 
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Your post is confusing because you're using no as number and no as no.

Perhaps you could clarify it a bit more.
 
The way you word your riddles is a big no-no!
 
42101000
:smile:
 
It has nly 6 digits
 
Lostinthought said:
It has nly 6 digits
Count again...
:smile:
 
Borek said:
The way you word your riddles is a big no-no!

A big number-number?
 
What about a big number-factorial_of_a_number ?
:smile:
 

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