Formula for mixing liquids of different temperatures?

Click For Summary
SUMMARY

The discussion focuses on calculating the correct mixture of water at different temperatures to achieve a target temperature of 40 degrees Celsius in a 3500-litre container. The user initially used a weighted average formula, resulting in 1166 litres of boiling water mixed with 2334 litres of 10°C water. While this method is generally acceptable for practical applications, the conversation highlights the importance of understanding the principles of thermal mixing and the potential need for precision in specific scenarios, such as avoiding scalding in a pool.

PREREQUISITES
  • Understanding of thermal mixing principles
  • Basic algebra for solving equations
  • Knowledge of temperature scales (Celsius)
  • Familiarity with practical applications of thermal expansion
NEXT STEPS
  • Research the formula for mixing liquids of different temperatures
  • Learn about thermal expansion and its effects on liquid volumes
  • Conduct small-scale tests for temperature mixing accuracy
  • Explore practical applications of thermal mixing in pool maintenance
USEFUL FOR

This discussion is beneficial for anyone involved in water management, such as pool operators, engineers, and individuals interested in precise temperature control in large volumes of liquid.

kenewbie
Messages
238
Reaction score
0
I'm going to fill a big container (3500 litres) with water. I'll use water from a hose, and boiled water, and I want to hit 40 degrees celsius.

Now, I figured that this was straight forward,

Temperature in hose = 10 C
Temperature of boiled water = 100 C

( 100 * X + (3500 - X) * 10 ) / 3500 = 40

Which gives 1166 litres of boiling water.

However, this assumes that 1 litre of 10 C water + 1 litre of 20 C water = 2 litres of 15 C water. In other words, that I can just add the temperatures together and then divide by the total amount of liquid.

Someone (who celsius was not able to provide a formula) said it is not as straight forward as that.. so, I'm looking for the formula for mixing liquids of different temperatures.

k
 
Science news on Phys.org
How precise do you need to be? I guess you could take thermal expansion into account if you wanted to, but the simple weighted-average method you used should be good enough for most applications.
 
Oh, ok then I am golden. I only need to be accurate enough to avoid boiling anyone that ventures into the pool :)

Thanks a lot.

k
 
You could also do a test by making 3.5 liters first, using 1.17 L of boiling water.
 
Yeah, I'll do a small scale test first, to make sure.

Thanks again.

k
 

Similar threads

  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 5 ·
Replies
5
Views
3K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 9 ·
Replies
9
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 53 ·
2
Replies
53
Views
7K
  • · Replies 2 ·
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
3K