Formulas for Copper (II) Chlorate

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SUMMARY

The correct formula for copper (II) chlorate is Cu(ClO3)2. This conclusion is based on the oxidation numbers of the elements involved, where the chlorate radical (ClO3) has an oxidation number of -1, and copper (Cu) has an oxidation number of +2. Therefore, two chlorate radicals are required to balance the charge of one copper atom, resulting in a neutral compound. The discussion emphasizes the importance of understanding oxidation states in determining chemical formulas.

PREREQUISITES
  • Understanding of oxidation numbers in chemistry
  • Familiarity with chemical formulas and nomenclature
  • Knowledge of polyatomic ions, specifically chlorate (ClO3)
  • Basic principles of chemical neutrality in compounds
NEXT STEPS
  • Study the concept of oxidation states in transition metals
  • Learn about polyatomic ions and their charges
  • Explore the naming conventions for ionic compounds
  • Review examples of chemical formula derivation using oxidation numbers
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Chemistry students, educators, and anyone interested in understanding chemical formulas and oxidation states in inorganic chemistry.

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What is the formula for copper (II) chlorate?

a. CuClOsubscript 3
b. Cu(ClOsubscript 3) subscript 2
c. CuCl
d. CuClsubscript 2

Please help if you don't mind.
 
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seve said:
What is the formula for copper (II) chlorate?

a. CuClOsubscript 3
b. Cu(ClOsubscript 3) subscript 2
c. CuCl
d. CuClsubscript 2

Please help if you don't mind.




I don't mind.What's your idea??

Daniel.
 
I believe it is A. I am pretty sure that B and C are wrong because of the oxidation numbers not equaling zero.

Am I correct in my thinking?
 
NO.
What is the ON for each element...??What about the radical "chlorate"...??

Daniel.
 
What is C?
 
What "C" are you talking about...??There's a Cl which is the chemical symbol for Chlore...

Answer the question regarding the ON-s...

Daniel.
 
Sorry, answer choice B.
 
Don't HIT AND RUN...How did u figure it out...??What was your logics??

Daniel.
 
By the process of elimination...

Seriously, though, I don't understand this concept. Can you just explain it to me?

Anyways, thank you for your time and effort if you are too busy.
 
  • #10
The chlorate radical ClO_{3} has ON -1 ,simply because the oxygen has ON -2 (as in most of its compounds) and the chlore has ON +5 (and you should figure out from the suffix "ate" and the lack of any prefix).
On the other side,the copper atom has ON +2 (because the problem says so,it may have ON +1 as well).
So to form a NEUTRAL MOLECULE,you need two radicals and one copper atom...

Daniel.
 
  • #11
Thanks! I got it.
 

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