In most metals, the atomic ions form a regular arrangement called a crystal lattice. The conduction electrons in the sea of electrons move through this lattice. The figure (Intro 1 figure) is a one-dimensional model of a crystal lattice. The ions have mass m , charge e , and an equilibrium separation b.
Suppose this crystal consists of aluminum ions with an equilibrium spacing of 0.30nm. What are the energies of the four lowest vibrational states of these ions?
The Attempt at a Solution
well i thought separation equilibrium = (h bar/mw)^0.5 from this i got the w angular frequency and then i use the vibrational formula (n-1)h bar * w i got these first four vibrational states 0.42ev,1.30ev,2,1ev,2,9ev but i got it wrong can anybody tell what i did wrong please thanks