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Homework Help: Fourier cosine/sine transforms

  1. Jun 6, 2006 #1
    why doesn't e^x have fourier cosine/sine transforms?
     
  2. jcsd
  3. Jun 6, 2006 #2

    Meir Achuz

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    It is too singular as x-->infty.
     
  4. Jun 7, 2006 #3
    could you please explain the meaning of singular?
     
  5. Jun 7, 2006 #4
    f(x) must vanish as x goes to infinity in order for the the Fourier transform of f(x) to exist
     
  6. Jun 8, 2006 #5
    i see!!! thank you very much!!!
     
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