# Fourier transform - why we need it?

1. Apr 6, 2015

### mickonk

Hi. I'm familiar with Fourier series but I have some hard times in learning Fourier transform. Why we use it? What's purpose of Fourier transform? Here is one signal and plot of Fourier transform of that signal:

What this graph tells us? Thanks in advance.

2. Apr 6, 2015

### davidbenari

I'll give you my novice interpretation of it, so be careful:

Fourier series are the discrete case of the fourier transform. This means that you are constructing a series where the arguments of the trigonometrics in your infinite series are integer multiples of the fundamental frequency. So the series looks like this (where a constant is added) $f(x)=a_o / 2 + \sum (a_n cos(n\pi x /l) + b_n sin (n\pi x /l)$. To make this more compact we use Eulers formula and say that the series is just $f(x)=\sum c_n e^{i n \pi x /l}$.

The thing is that this discrete representation is periodic. It will always repeat itself and this is can be in some cases completely useless.

Suppose you want to construct a pulse which represents some signal. You want it to be localized in space (that is, not having an infinite repeating pattern).

Therefore you have to use arguments that are continuous and not discrete. You therefore use the fourier transform to represent this signal or pulse. There is a mathematical and rigorous way to prove this but look at the similarity of the fourier transform with the sum of exponentials in this case:

$f(x) = \frac{1}{\sqrt{2\pi}} \int_{-\infty}^{\infty} g(\omega) e^{i\omega x} d\omega$

Its just a continuous sum of infinitesimals where the constant in the beginning is not of crucial importance to see what is happening.

Your question is about the importance of the function $g(\omega)$. Well if you take the analogy with the sum of exponential terms as far as I take it, well, that function is the amplitudes of your trigonometric functions in the series. So $g(\omega)$ is telling you the distribution of the weights of each frequency present in your pulse.

3. Apr 8, 2015

### mickonk

One more thing. Let's say I have some circuit with nonperiodic voltage source and I want to find response of some component in circuit, for example voltage across component. Using Fourier transform I should "convert" my excitation from time domain to frequency domain, find response in frequency domain using standard techniques (using KVL and KCL, or Nodal analysis etc), and then apply inverse Fourier transform on response I got in frequency domain to get response in time domain, right?

4. Apr 8, 2015

### davidbenari

I've never done applications of the Fourier transform to electricity, to be honest. What you said makes sense to me though.

5. Apr 19, 2015

### jssamp

Fourier analysis transforms time domain signal into the frequency domain. There are several situations where it is invaluable like in digital signal processing for communications or image analysis, simplifying calculations such as transforming a difficult convolution in time into multiplication in frequency. The Fourier transform also provides methods to operate on signals of different classes, continuous, discrete, periodic or not.

If you work with electric circuits, especially filters, or signal processing Fourier is one of your most powerful tools.