- #1
Blairo
- 1
- 0
Hello,
I'm having some trouble understanding the concept of two function convolution in Fraunhofer diffraction.
Let's say I have an aperture function in the shape of some cosine function (which is always above zero), and I want to calculate the transmission function if I only illuminate 3 such "slits" (so I capture 3 peaks of cosine aperture function). In order to do that, I was told to take the convolution of two Fourier transforms: the transmission function of cosine aperture illuminated over infinite slits and the transmission function of the Rect. function (some kind of box, which captures the 3 peaks of cosine function), which is a Sinc. function.
Is this correct? I don't quite get the physical meaning of convolution in this particular case.
Thanks for any explanations.
I'm having some trouble understanding the concept of two function convolution in Fraunhofer diffraction.
Let's say I have an aperture function in the shape of some cosine function (which is always above zero), and I want to calculate the transmission function if I only illuminate 3 such "slits" (so I capture 3 peaks of cosine aperture function). In order to do that, I was told to take the convolution of two Fourier transforms: the transmission function of cosine aperture illuminated over infinite slits and the transmission function of the Rect. function (some kind of box, which captures the 3 peaks of cosine function), which is a Sinc. function.
Is this correct? I don't quite get the physical meaning of convolution in this particular case.
Thanks for any explanations.