Free body diagrams and adding forces

AI Thread Summary
The discussion focuses on solving for the x- and y-components of acceleration (ax and ay) for a 2.6 kg object in two free-body diagrams, given forces F1 = 5 N and F2 = 3 N. Participants emphasize the importance of correctly calculating the components of the 3 N force using sine and cosine functions to find net forces in both x and y directions. There are concerns about accuracy in calculations, particularly regarding significant figures and rounding. The calculations for ax and ay are discussed, with specific values provided, but some participants question the correctness of the results, particularly for ay. The conversation concludes with a suggestion to apply the same method used for Diagram A to Diagram B.
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Homework Statement


In each of the two free-body diagrams, the forces are acting on a 2.6 kg object. For each diagram, find the values of ax and ay, the x- and y-components of the acceleration, with F1 = 5 N and F2 = 3 N. Picture is attached.

(a) Diagram A
ax =____ m/s2
ay =____ m/s2
(b) Diagram B
ax =____ m/s2
ay =____ m/s2

Homework Equations





The Attempt at a Solution



I tried to use sin and cos. I don't think I am adding the forces up right. Help! Due today! I am getting decimal numbers... I used a = F/M.
 

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It is always better to your calculations. We must know what mistakes you have made in adding the forces. That gives un an idea about your level of understanding.
In the first problem, you have to x and y components of 3 N force. Then find net Fx and net Fy which gives you ax and ay.
 
For x comp. of 3N = 1.02606 y= 2.81908

My guess for F net is 2.97394...

ax = F/M 1.14382?ay = .000354 wrong
 
Show your ay calculation.
How much significant numbers you are expexted to write in the answer?
 
Ax : 3sin(20)=1.02606
F = -1.02606-1+5 = 2.97394 = 2.97394/2.6 = 1.14382

Ay : 3cos(20)= 2.81908
F = -2.81908 + 2.82 = 0.000922 = 0.000922/2.6 = 0.000355
 
gbedenba said:
Ax : 3sin(20)=1.02606
F = -1.02606-1+5 = 2.97394 = 2.97394/2.6 = 1.14382

Ay : 3cos(20)= 2.81908
F = -2.81908 + 2.82 = 0.000922 = 0.000922/2.6 = 0.000355
Looks good.
 
it says Ay is wrong.

For diagram B...how would I do it?
 
gbedenba said:
it says Ay is wrong.
Looks right to me. Perhaps they want you to round it off to zero (which is the proper answer, given the significant digits involved).
For diagram B...how would I do it?
The same way you did A.
 
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