Freebody Diagram for Crate Lifted with Steel Cable at Decreasing Speed

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Homework Help Overview

The problem involves creating a free body diagram for a crate being lifted by a steel cable at a decreasing speed. The focus is on accurately labeling the forces acting on the crate in the vertical direction.

Discussion Character

  • Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the appropriate forces to include in the diagram, questioning the relevance of horizontal forces and the correct labeling of tension. There is also a consideration of how to represent the concept of decreasing speed in the diagram.

Discussion Status

Some participants have provided guidance on the labeling of forces, suggesting that only the tension force should be included in the diagram. There is an ongoing exploration of the implications of the crate being lifted and how that relates to the forces depicted.

Contextual Notes

Participants are navigating the constraints of the homework prompt, which specifies the need to label the diagram correctly while considering the dynamics of the situation, such as the decreasing speed of the crate.

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Homework Statement



A crate is being lifted by a steel cable at a decreasing speeed. Label everything in the diagram.


The Attempt at a Solution




[PLAIN]http://img163.imageshack.us/img163/5764/drawk.png

This is what I did but it is wrong, how would I draw it to show the decreasing speed and also the lifted part?
 
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the crate (the lifted part) is being lifted up...there's nothing going on in the horizontal direction, so those horizontal forces don't belong there. The vertical ones are OK, although usually the force you have labeled FN is usually called FT or just T, because it is a tension force pulling away from the crate. That's all you need to do in a free body diagram. Taking into account the decreasing speed would be asked for as a 'part b' question.
 
Ok thanks, I understand. Since there is no labeled horizontal forces I don't need the Fa and Ff.

But since its being lifted isn't there an Fa or is it just FT.
 
homevolend said:
Ok thanks, I understand. Since there is no labeled horizontal forces I don't need the Fa and Ff.

But since its being lifted isn't there an Fa or is it just FT.
That is right, the applied force is the tension force, in this problem. Don't put in 2 forces at the top, just the one. Here's a tip...when you draw free body diagrams, you note and label the forces acting on the object, and their direction. There are basically 2 general types of forces : action at a distance forces (like gravity forces (weight) or magnetic forces); and so called 'contact' forces, where there has to be contact with the object in order for there to be a force. Contact forces include friction forces, tension forces, spring forces, normal forces, applied pushing or pulling forces, etc.
 

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