Frequency of light to eject electrons from gold

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Homework Help Overview

The discussion revolves around determining the frequency of light required to eject electrons from a gold surface, given the maximum kinetic energy of the ejected electrons and the work function of gold.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the relationship between photon energy, frequency, and the work function. There are attempts to apply formulas related to kinetic energy and work function to find the frequency.

Discussion Status

Some participants have provided guidance on converting energy units and understanding the relationship between energy and frequency. There is an indication of multiple interpretations and approaches being explored, but no explicit consensus has been reached.

Contextual Notes

One participant noted the importance of posting in the correct forum to receive specific guidance, suggesting that there may be additional rules or information typically provided in the homework section.

mhooker_10
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What frequency of light must be used to eject electrons from a gold surface with a maximum kinetic energy of 6.48×10(−19)J ?

The work function of gold is 4.58 eV.

f=
 
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You have to at least attempt an answer to a homework question.
Whats the energy of a photon, in terms of frequency?
 


I used the formula for K(max) and solved for f and got 6.91 x 10(33)...and that not the right answer
 


So you need to supply enough energy to overcomethe work function and then supply the KE.
So convert the work function into joules and add to the ke.
Then you just need the energy of aphoton in terms of frequency.

oops - you didn't post in the HW forum, so didn't get the list of things to do.
 


Nevermind...I figured it out
 

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