Frequency of photons emitted from electrons

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SUMMARY

The discussion centers on calculating the frequency of a photon emitted when an electron transitions from the fourth energy level to the first in a hydrogen atom. The energies provided are -21.76 x 10^-19 Joules for the first level and -0.85 eV for the fourth level. The correct calculation involves converting the energy from eV to Joules, leading to a frequency of 3.09 x 10^15 Hz, which aligns with the book's answer. The confusion arose from the initial incorrect interpretation of energy units.

PREREQUISITES
  • Understanding of quantum mechanics principles
  • Familiarity with energy level calculations in hydrogen atoms
  • Knowledge of the relationship between energy, frequency, and Planck's constant
  • Ability to convert electron volts (eV) to Joules
NEXT STEPS
  • Study the concept of energy level transitions in quantum mechanics
  • Learn about Planck's equation and its applications in photon energy calculations
  • Explore the conversion between electron volts and Joules in detail
  • Investigate the implications of negative energy values in atomic physics
USEFUL FOR

This discussion is beneficial for physics students, educators, and anyone interested in quantum mechanics, particularly those studying atomic transitions and photon emission.

Abidal Sala
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Homework Statement


The energy of the electron in the first and forth levels in a hydrogen atom are: (21.76*10^-19), (-0.85) e.V.. the electron moved from the forth level to the first level with one leap. Calculate:
The frequency of the emitted photon from the atom

Homework Equations


ΔE = hf

The Attempt at a Solution


f = ΔE / h
f = [(-0.85) - (21.76*10^-19)] / 6.6*10^-34
f = -1.2878*10^33 Hz ..
I get that answer while the answer given in the book is 3.09*10^15 Hz, I'm confused..
 
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i think that energy in the first level is given in Joule (-21.76*10^-19) and the second is in eV.so you have to convert both energy levels to Joule.since electron's charge is negative, it's energy in presence of positive charge's potential is negative. so f=(-.85*1.602*10^-19--21.76*10^-19)/(6.6*10^-34)=3.09*10^15 Hz
 

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