Highest Frequency emitted by bremsstrahlung

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Homework Help Overview

The problem involves calculating the highest frequency of electromagnetic waves emitted by electrons accelerated through a potential difference in a television tube. The context is within the subject area of electromagnetism and quantum mechanics, specifically focusing on bremsstrahlung radiation.

Discussion Character

  • Exploratory, Assumption checking, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss the relationship between the energy of the electrons and the frequency of the emitted photons, questioning the assumptions made regarding energy conversion and unit consistency.

Discussion Status

Participants are actively engaged in identifying potential errors in calculations and unit conversions. There is a recognition of the need to ensure proper unit usage, particularly in converting electron volts to joules, and the implications of using different constants in calculations.

Contextual Notes

There is mention of the work function of the tube, which is not provided, and discussions about the appropriate use of physical constants in different unit systems. The original poster's calculations are noted to be significantly off from expected results, prompting further examination of the assumptions and methods used.

Blanchdog
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Homework Statement


Electrons are accelerated in a television tube through a potential difference of 8.5 kV. What is the highest frequency of the electromagnetic waves emitted when these electrons strike the screen of the tube?

Homework Equations


λ = c/f
E (of the electron) = V*e
E (of the photon) = h*c/λ

The Attempt at a Solution



Without knowing the work function of the tube, the best I could come up with was to assume that all the kinetic energy of the electron was transferred to the photon and set the energies equal to one another. Simple algebra substituting the wavelength for it's definition in terms of frequency gives the equation:

f = V*e/h​

Substitution of numeric values then gives

f = 8500*1.6E-19/6.58E-16 = 2.067 Hz

EDIT: I accidentally used h-bar instead of h. It still comes out different from the desired answer though.
f = 8500*1.6E-19/4.14E-15 = .329 Hz​

The online homework I have says that I am off by 18 orders of magnitude: the correct answer is 2.1E18

Where am I going wrong here?
 
Last edited:
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Blanchdog said:
f = V*e/h​
Substitution of numeric values then gives

f = 8500*1.6E-19/6.58E-16 = 2.067 Hz​
I think you forgot the conversion from eV to Joules for the electron's initial energy...?
 
Units. Always write out the units.
 
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berkeman said:
I think you forgot the conversion from eV to Joules for the electron's initial energy...?
He did not. He inserted the Planck constant in units of eV s instead of in SI units when everything else is in SI units.
 
Orodruin said:
He did not. He inserted the Planck constant in units of eV s instead of in SI units when everything else is in SI units.
Ah, thanks!
 
berkeman said:
I think you forgot the conversion from eV to Joules for the electron's initial energy...?

The dimensional analysis works out, currently the units are eV/(eV*s), leaving 1/s = Hz. I did however accidentally use h-bar instead of h, so fixing that:

f = 8500*1.6E-19/4.14E-15 = .329 Hz​
 
Blanchdog said:
The dimensional analysis works out, currently the units are eV/(eV*s)
Dimensional analysis is about getting the right physical dimension. Your problem is with units, not with dimensions. If you want to use eV as your energy unit, you will be using units of the elementary charge for charges. Your numerator with the numerical values you inserted have the units V C (i.e., Joules), not eV.
 
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Orodruin said:
Dimensional analysis is about getting the right dimension Your problem is with units, not with dimensions. If you want to use eV as your energy unit, you will be using units of the elementary charge for charges. Your numerator with the numerical values you inserted have the units V C (i.e., Joules), not eV.

Ahhhhh! Thank you, you're exactly right.
 
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