(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

2 masses, m_{1}and m_{2}, m_{1}being on top of m_{2}and m_{2}is heavier than m1. [tex]\mu[/tex]_{s}is the coefficient of static friction anywhere and [tex]\mu[/tex]_{k}is the coefficient of kinetic friction between the floor and m_{2}. What is the maximum acceleration m_{2}can have for m_{1}not to fall off?

2. Relevant equations

just FBDs.

3. The attempt at a solution

for m1

N_{1}=m_{1}g from [tex]\Sigma[/tex]F_{y}

for m2

N_{2}=(m_{1}+m_{2})g

so for [tex]\Sigma[/tex]F_{x}=F_{app}-[tex]\mu[/tex]_{k}(m_{1}+m_{2})g

I included a F_{app}variable there. But i have the feeling that it doesn't really matter. Anyway, tinkering with m_{1}[tex]\Sigma[/tex]F_{x}

[tex]\Sigma[/tex]F_{x}=m_{1}a_{2}-[tex]\mu[/tex]_{s}m_{1}g

which you can see that i equated m_{1}with the acceleration of m_{2}.

which when manipulated will give (I assumed that m_{1}'s [tex]\Sigma[/tex]F_{x}=0 for it not to move)

a_{2}=[tex]\mu[/tex]_{s}g

but this is incredibly wrong. I'm quite lost now.

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# Homework Help: Friction between 2 masses and maximum acceleration

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