Thegiver431 Messages 13 Reaction score 1 Thread starter Nov 19, 2014 #1 how do you find friction force when applied force is at an angle, this is on a flat horizontal surface.
how do you find friction force when applied force is at an angle, this is on a flat horizontal surface.
Dale Mentor Insights Author Messages 36,992 Reaction score 15,979 Nov 19, 2014 #2 Usually you will need to break at least one force into components.
Maged Saeed Messages 123 Reaction score 3 Nov 20, 2014 #3 the static frictional force is : $$u_sF_n$$ [Us] is constant and [F_n] is the wieght of the object the force is applied to plus the vertical component of the force ,, I think :) Remember that the frictional force is always in opposite direction of the applied force , that means they would have a different signs Last edited: Nov 20, 2014
the static frictional force is : $$u_sF_n$$ [Us] is constant and [F_n] is the wieght of the object the force is applied to plus the vertical component of the force ,, I think :) Remember that the frictional force is always in opposite direction of the applied force , that means they would have a different signs
CWatters Science Advisor Homework Helper Gold Member Messages 10,546 Reaction score 2,324 Nov 20, 2014 #4 Fn is the force normal to the surface (it need not be the "weight" of the object or even "vertical"). In these two examples the normal force is the weight of the object modified by the vertical component of the applied force F. http://philschatz.com/physics-book/resources/Figure_06_01_07a.jpg in a) that would be Fn = mg+FSin(25) in b) that would be Fn = mg-FSin(25) Since friction is proportional to Fn that means b is easier than a)
Fn is the force normal to the surface (it need not be the "weight" of the object or even "vertical"). In these two examples the normal force is the weight of the object modified by the vertical component of the applied force F. http://philschatz.com/physics-book/resources/Figure_06_01_07a.jpg in a) that would be Fn = mg+FSin(25) in b) that would be Fn = mg-FSin(25) Since friction is proportional to Fn that means b is easier than a)