Friction Force Calculation at an Angle on Flat Surface

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To calculate the friction force when an applied force acts at an angle on a flat surface, it is essential to break the applied force into its components. The static frictional force is determined by the equation u_sF_n, where u_s is the coefficient of static friction and F_n is the normal force. The normal force is influenced by the object's weight and the vertical component of the applied force, which can either add to or subtract from the weight depending on the angle of application. Therefore, the frictional force is always opposite to the direction of the applied force. This analysis shows that scenarios where the vertical component of the applied force reduces the normal force result in lower friction, making movement easier.
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how do you find friction force when applied force is at an angle, this is on a flat horizontal surface.
 
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Usually you will need to break at least one force into components.
 
the static frictional force is :

$$u_sF_n$$

[Us] is constant and [F_n] is the wieght of the object the force is applied to plus the vertical component of the force ,, I think :)

Remember that the frictional force is always in opposite direction of the applied force , that means they would have a different signs
 
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Fn is the force normal to the surface (it need not be the "weight" of the object or even "vertical").

In these two examples the normal force is the weight of the object modified by the vertical component of the applied force F.
http://philschatz.com/physics-book/resources/Figure_06_01_07a.jpg

in a) that would be

Fn = mg+FSin(25)

in b) that would be

Fn = mg-FSin(25)

Since friction is proportional to Fn that means b is easier than a)
 

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