Friction Force & Direction for 925 kg Car at -12.2m/s2 Acceleration

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Homework Help Overview

The discussion revolves around determining the frictional force and its direction for a car with a specified mass and acceleration. The context involves concepts from dynamics and friction in physics.

Discussion Character

  • Exploratory, Conceptual clarification, Problem interpretation

Approaches and Questions Raised

  • Participants explore the relationship between mass, acceleration, and frictional force, with some suggesting the use of free-body diagrams and equations of motion. Questions arise regarding the coefficient of friction and its role in calculating the frictional force.

Discussion Status

There are multiple lines of reasoning being explored, including the use of free-body diagrams and the relationship between normal force and friction. Some participants provide guidance on focusing on the forces involved without overcomplicating the problem.

Contextual Notes

Participants note the need to find the coefficient of friction and question the assumptions regarding the forces acting on the car, including the normal force and gravitational force.

drinkingstraw
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The average rate of acceleration for a breaking car was -12.2m/s2. If the car had a mass of 925 kg, find the frictional force and direction.

a = -12.2m/s2
m = 925 kg
Fn = 9074.25 N

This is what I've figured out. I don't know how to find the coefficient of friction. If I get the coefficient I think I can multiply it by the normal force to get the frictional force.
 
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You're complicating the problem unnecessarily.

The question asks only for the frictional force and direction. Try drawing a free-body diagram for the car and then write down the F=ma equations.
 
F_f = u*F_n

F_n = mgF_f = u *mg

find u
 
The problem only asks for F_f :smile:
The free body diagram is the way to go. Fn and Fg cancel out. What other force or forces provide the acceleration?
 

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