- #1
rsq_a
- 107
- 1
Is there an easy way to show that the system:
[tex]
\begin{align}
x_1' &= p_{11} x_1 + p_{12} x_2 + \ldots + p_{1n} x_n \\
x_2' &= p_{21} x_1 + p_{22} x_2 + \ldots + p_{2n} x_n \\
\ldots &= \ldots \\
x_n' &= p_{n1} x_1 + p_{n2} x_2 + \ldots + p_{nn} x_n
\end{align}
[/tex]
must be equivalent to a single nth order differential equation, like
[tex]
a_n y^{(n)} + a_{n-1} y^{(n-1)} + \ldots + a_0 y_n = 0
[/tex]
All the [tex]p_{ij} = p_{ij}(t)[/tex] and [tex]a_i = a_i(t)[/tex]. In the case that n = 2, it's easy to show just by manipulation. I assume that it's true in general, but I can't find a slick way to do it.
[tex]
\begin{align}
x_1' &= p_{11} x_1 + p_{12} x_2 + \ldots + p_{1n} x_n \\
x_2' &= p_{21} x_1 + p_{22} x_2 + \ldots + p_{2n} x_n \\
\ldots &= \ldots \\
x_n' &= p_{n1} x_1 + p_{n2} x_2 + \ldots + p_{nn} x_n
\end{align}
[/tex]
must be equivalent to a single nth order differential equation, like
[tex]
a_n y^{(n)} + a_{n-1} y^{(n-1)} + \ldots + a_0 y_n = 0
[/tex]
All the [tex]p_{ij} = p_{ij}(t)[/tex] and [tex]a_i = a_i(t)[/tex]. In the case that n = 2, it's easy to show just by manipulation. I assume that it's true in general, but I can't find a slick way to do it.