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Function transformations

  1. Jan 30, 2014 #1
    Hello all, I need some help to clear my doubts.

    Why does a horizontal translation (f(x + c)) move to the left if c is positive?

    Can someone graphically explain what effect a stretch and compression (vertical and horizontal) has on the original parent function?

    Similar to the first question, why does f(ax) actually stretch by a factor of 1/a instead of a?

    Thanks, I might have more questions later.
  2. jcsd
  3. Jan 31, 2014 #2
    Is you graph y1=f(x) and y2=f(x+C) and then compare them, whatever "y1" you see at any "x1" will be seen to the left (assuming C>0) at x2="x1-C" for y2 because y2 = f(x2+C) = f(x1-C+C) = f(x1) = y1.
    f(Ax) will horizontally thin the graph by a factor of "A" (or stretch it by 1/A)
    Af(x) will vertically stretch the graph by a factor of "A".
  4. Jan 31, 2014 #3
    Take a look at this simple example, suppose ##f(x)=x##, a simple straight line through the origin. If ##x=0##, then ##f(x)=0## as well. But if you take ##f(x+a)##, the origin will be at ##-a##. If you draw the line, the origin will move to the left because the origin is now in negative part of the x-axis.
  5. Feb 1, 2014 #4


    Staff: Mentor

    The origin doesn't move around, but the x-intercept does.
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