Gauss' Law - Electric Flux and Electric Field

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Homework Help Overview

The discussion revolves around a problem involving Gauss' Law, specifically focusing on electric flux and electric fields generated by a uniformly distributed charge within a hollow sphere. The original poster presents a scenario with a 2 C charge and seeks to determine the electric flux and the electric field at a distance of 200 cm from the sphere.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to apply the formula for electric flux and questions how to incorporate both the radius of the sphere and the distance from it when calculating the electric field. Some participants clarify that the electric field outside the sphere can be treated as if the charge were concentrated at a point at the center of the sphere.

Discussion Status

The discussion is ongoing, with participants providing insights into the application of Gauss' Law and the nature of electric fields. There is a request for verification of the calculations presented, indicating a desire for further exploration of the problem without definitive solutions being provided.

Contextual Notes

Participants are navigating the implications of the problem's setup, including the relevance of the sphere's radius and the distances involved in the calculations. There is a mention of the need for independent verification of the original poster's answers, highlighting the collaborative nature of the inquiry.

Yuxtapuesto
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Homework Statement



A 2 C charge is spread uniformly in a hollow sphere with a radius of 50 cm.

a) What is the electric flux?

b) What is the magnitude and direction of an electric field 200 cm away?

Homework Equations



Electric flux = q/(permittivity of free space)

E = q/4(pi)(permittivity of free space)r2

q = charge
The permittivity of free space = 8.85 x 10-12 C2/(N*m2)
r = radius

The Attempt at a Solution



Because the electric flux = the enclosed net charge divided by the permittivity of free space (approx. 8.85 x 10-12) I attempted to use this equation. Using 2 C as the net charge, I found the answer to be about 2.26 N*m2/C

I had no idea how to solve the second part of the question, but referenced my book and found this equation:

E = q/4(pi)(permittivity of free space)r2

q = charge
The permittivity of free space = 8.85 x 10-12 C2/(N*m2)
r = radius

My problem with this equation is that it doesn't seem to incorporate both the 50 cm and the 200 cm distances that are given within the question, but using 200 cm as the value of r, I calculated the answer to part b as 8.99 x 109 N/C

Any help would be greatly appreciated!
 
Last edited:
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The reason it doesn't incorporate the 50cm i.e. the radius of the sphere is that outside the sphere the electric field is the same as if you concentrated the charge spread throughout the sphere into a point charge at the center of the sphere.

This can be visualised easily by the first equation you gave. The one for the flux. (We are talking about a reference point outside of the sphere) You said that the flux is proportional to the enclosed net charge, hence if it was the flux of a point charge 2C you would get the same result, since the net charge enclosed is the same, as of the sphere.
 
Thank you. Can you / anyone possibly verify these answers?
 
What do you mean by verifying them? you theory is ok... You just have to substitute thenumerical values...
 
I mean that if someone could solve this problem independent of my work and share his or her answer with me, I would greatly appreciate it.
 
What is the formula for electric flux
 

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