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matematikuvol
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[tex]\oint_S \vec{A}\cdot d\vec{S}=\int_V div\vec{A}dv[/tex]
Suppose region where [tex]\vec{A}(\vec{r})[/tex] is diferentiable everywhere except in region which is given in the picture. Around this region is surface [tex]S'[/tex]. In this case Gauss theorem leads us to
[tex]\int_S \vec{A}\cdot d\vec{S}+\int_S \vec{A}\cdot d\vec{S}=\int_{V'} divAdv[/tex]
Am I right?
Suppose region where [tex]\vec{A}(\vec{r})[/tex] is diferentiable everywhere except in region which is given in the picture. Around this region is surface [tex]S'[/tex]. In this case Gauss theorem leads us to
[tex]\int_S \vec{A}\cdot d\vec{S}+\int_S \vec{A}\cdot d\vec{S}=\int_{V'} divAdv[/tex]
Am I right?
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