That's the one thing I did not check.Jrlinton said:
A Gaussian Shell is a hypothetical spherical shell with a uniform charge distribution. It is a common model used in physics and mathematics to simplify the analysis of electric fields and potential.
The electric field for a Gaussian Shell is calculated using Gauss's Law, which states that the electric flux through a closed surface is equal to the total charge enclosed by that surface divided by the permittivity of free space. This can be written as: E = Q/ε0r2, where E is the electric field, Q is the total charge, and r is the distance from the center of the shell to the point of interest.
The net electric field inside a Gaussian Shell is zero. This is because the electric field at any point inside the shell is cancelled out by the electric field from the opposite side of the shell, resulting in a net electric field of zero.
The net electric field outside a Gaussian Shell is the same as the electric field from a point charge with the same total charge as the shell located at the center of the shell. This can be calculated using Coulomb's Law: E = kQ/r2, where E is the electric field, k is the Coulomb's constant, Q is the total charge of the shell, and r is the distance from the center of the shell to the point of interest.
The electric field of a Gaussian Shell and a solid sphere are similar only at points outside the objects, where they both follow the inverse-square law. Inside the objects, the electric field of a solid sphere is not uniform and depends on the distance from the center, while the electric field of a Gaussian Shell is zero. Additionally, the electric field at the surface of a solid sphere is not perpendicular to the surface, while the electric field at the surface of a Gaussian Shell is always perpendicular.