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Gaussian Surfaces and infinite lines of charge

  1. Sep 15, 2013 #1
    So I've been wondering..
    from my previous post: https://www.physicsforums.com/showthread.php?p=4500082#post4500082

    if we have a plane of infinite charge, then electric field does not depend on distance

    however, for a infinite line of charge:
    If we use a cylinder with radius 'r' as our gaussian surface then
    the electric field has the equation

    E = (charge density)/ (2∏ε * r)

    which now depends on the radius of the cylinder.

    This suggests that the electric field actually will have different values for different radius values
    which (i feel) don't line up with the conclusion I reached in my first thread 'if we have a plane of infinite charge, then electric field does not depend on distance'

    Any help?
     
  2. jcsd
  3. Sep 16, 2013 #2

    Simon Bridge

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