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## Homework Statement

a)A charge Q=10nC is placed at the origin, which is the centre of a cube with side lengths a=1cm whose faces are perpendicular to the x,y and z axis. What is the total flux through the box and what is the average of the perpendicular component of the electric field on the right hand face centred on (0, a/2, 0)?

b)Now a second charge, -Q, is placed at (0,a,0). Now what is the total flux and the average fo the perpendicular component of the electric field at (0,a/2,0)?

## Homework Equations

flux=Q/eo

so i was able to calculate the flux easily, but i dont understand what is meant by the average perpendicular component of the electric field

the only thing i can think of it that EA=Q/eo, so i just solve for E? is that right

for the second part, wouldnt the total flux still be the same, because the second charge isnt enclosed in the cube