Biology Gene Mutation Equations and Solution Explanation without Character Count

[jsmith613]

Homework Statement

Homework Equations

The Attempt at a Solution

From what I can see in the data given there must be at LEAST 3 mutations
I found 5:
Initial: UCU UAU GGC
Final: UAU (1 mutation) UUA (2 mutaions) UUG (2 mutations)
or
Final: UAU (1 mutation) CUU (2 mutaions) UUG (2 mutations)

The answer given is:

UAC UUA UGG;
Firstly UAC = 2 mutations so total of 6 mutations
secondly how is this a two single base mutation?

thanks

 

[badbrain103]

For the answer given for leucine (UCU) going to tyrosine (UAC), there would need to be one single base mutation from C -> A and U -> C. There is two single base mutations.

For tyrosine (UAU) going to leusine (UUA), there would need to be a single base mutation in A in tyrosine mutating to U, and the last U in tyrosine mutating to A. That's two single base mutations.

I think you can figure the last one out if it is GGU mutating to UGG.