- #1
Notaphysicsmajor
- 12
- 0
Hello,
Reviewing for the test and there are still some things I'm not sure about so I thought I'd ask here and hopefully come across someone that can help.
I swear I knew this, but I have not been diligently reviewing as much as I should so I think I forgot and became confused.
When a battery is connected to the circuit with a capacitor, what exactly is going on? From what I remember, the conductor connecting the negative side (for simplicity and less confusion refer to this as side one) of the battery with one side of the capacitor will gain electrons from the battery and accumulate electrons on that side of the capacitor. Because it has accumulated electrons on one side of the capacitor, and the other side (side two) of the capacitor being connected to the positive end of the battery, the other side of the capacitor will transfer it's electrons from the capacitor to the positive end of the battery as electrons are attracted towards positive charges and of the repulsive force of the excess electrons accumulated on the opposite capacitor. Is this correct?
What I'm confused on is HOW the electrons on the negative charges accumulate on the plate that already has an equal amount of electrons and protons, in that wouldn't it the electrons coming onto side one of the capacitor have to experience a force to overcome the repulsive force the electrons already on the plate emitted? Or am I thinking of it backwards in that first the positive end of the battery would attract the electrons from the side of the capacitor it is connected to, which then would allow the accumulation and attracted of other electrons onto the other plate?
I like to think I have a good conceptual grasp on everything else related to circuits, but I'm not quite convinced of HOW the charges are moving and where the force is coming from that is being applied to the charges.
Reviewing for the test and there are still some things I'm not sure about so I thought I'd ask here and hopefully come across someone that can help.
I swear I knew this, but I have not been diligently reviewing as much as I should so I think I forgot and became confused.
When a battery is connected to the circuit with a capacitor, what exactly is going on? From what I remember, the conductor connecting the negative side (for simplicity and less confusion refer to this as side one) of the battery with one side of the capacitor will gain electrons from the battery and accumulate electrons on that side of the capacitor. Because it has accumulated electrons on one side of the capacitor, and the other side (side two) of the capacitor being connected to the positive end of the battery, the other side of the capacitor will transfer it's electrons from the capacitor to the positive end of the battery as electrons are attracted towards positive charges and of the repulsive force of the excess electrons accumulated on the opposite capacitor. Is this correct?
What I'm confused on is HOW the electrons on the negative charges accumulate on the plate that already has an equal amount of electrons and protons, in that wouldn't it the electrons coming onto side one of the capacitor have to experience a force to overcome the repulsive force the electrons already on the plate emitted? Or am I thinking of it backwards in that first the positive end of the battery would attract the electrons from the side of the capacitor it is connected to, which then would allow the accumulation and attracted of other electrons onto the other plate?
I like to think I have a good conceptual grasp on everything else related to circuits, but I'm not quite convinced of HOW the charges are moving and where the force is coming from that is being applied to the charges.