General relativity and tidal forces

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Tidal forces on Earth are primarily explained by Newton's theory of gravitation, but general relativity (GR) offers a more complex understanding, particularly in strong gravitational fields where relativistic effects can double the predicted tidal strength. In GR, tidal forces arise from the curvature of spacetime, with different parts of a body following distinct geodesics, which could lead to structural stress if not countered by internal forces. The Riemann curvature tensor's components can describe these tidal forces, linking them to the electrogravitic tensor that relates to static gravity. However, the discussion highlights a challenge in reconciling the effects of rotation and tangential velocities in bodies under tidal forces, particularly in tidal lock scenarios, raising questions about the mechanics of maintaining structural integrity without shearing. Overall, the complexities of GR provide a nuanced framework for understanding tidal forces beyond Newtonian approximations.
  • #61
Nugatory said:
The relativistic effects that matter across a light-year (about 1016 meters) are completely irrelevant at the diameter of the moon (less than 107 meters. There are simply no relativistic phenomena involved in understanding the tidal lock of these systems (yes, you CAN solve them using the methods of the GR gravitational theory... but the first step in that solution is to apply the weak-field approximation and that gives you the same results as Newtonian gravity).

Bandersnatch is correct. If no torque is applied to the non-relativistic rotating rod it will be straight (although if has been elastically deformed by an applied torque it will take a moment for the deformation to relax and the rod to regain that undeformed straight shape). The only reason for the outer edge to lag would be drag, atmospheric or otherwise.

I was not talking about relativistic effects, i was talking about deformation due to torque. I think the point of our misunderstanding is that you consider that the torque is not constant, but if the force from gravity is constant, so is the torque. And this force is always greater on the near side. Think of it this way: the law of inertia states the if there are no forces on a body, it will remain in its rest state, either traveling at a constant linear velocity or standing still (which are the same thing). To maintain a stable curved path, like an orbit, the centripetal acceleration must be constant. This constant force generates a constant torque, like in a mery go round. If you don't hold on to something, you will fly off at the tangent. This must mean a constant centripetal force, and if the body is not falling towards the central mass, but orbiting, there is a constant force holding it in its curved path. This constant force is gravity, and it generates a constant torque. Why do you believe the torque ceases?
 
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  • #62
altergnostic said:
I agree, but you are considering the body after it is in tidal lock. The point is that there is a torque for the body to reach tidal lock, and my argument is that the body will reach tidal lock but will suffer shearing.
You're argument is wrong, and has gone on far too long.

I haven't seen tide lock explained by heat the way you state, could give me a reference?
This is old, old stuff, some going back to George Darwin and A.E.H. Love. More recently, but still old stuff,

Goldreich P. and Soter S. (1966). Q in the Solar System. Icarus 5, 375-389.
MacDonald, G.J.F (1964). Tidal Friction, Rev. Geophsys 2, 467-541.

You don't even understand the basics, and you are trying to argue? Thread locked.
 

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