General Solution and Number of Solutions in Z5 Field for X+Y-Z=1 Equation

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find a general solution and the number of solutions in Z5 field
of this equation:

X+Y-Z=1




i know i need to
y=0 z=1
y=1 z=0
but what next?
 
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Z5? The integers mod 5? Then X and Y can be ANYTHING as long as you pick Z=X+Y-1, can't they? How many solutions is that?
 
z5 is mod 5

i need to find the global solution for that equation?
 
There are LOTS of solutions. 1+0-0=1, 1+3-3=1, 4+3-1=1, etc etc. Read my message again.
 
how to find a general solution?
 
Read my message #2 again. I told you.
 
so its (1-y+z,y,z)
i know that there is endless solutions
but doesn't mod 5 cuts them
into 5 solutions?
 
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I would say you have 5 different values for Y and five different values for Z, then X is determined. How many possible (Y,Z) pairs?
 
25? possibilities
 
  • #10
transgalactic said:
25? possibilities

That would be my answer.
 
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