Generating a Permutation Matrix P for All Permutations of A

AI Thread Summary
Generating a permutation matrix P that allows for cycling through all permutations of a matrix A by repeated application is not feasible for sizes greater than 2. The discussion highlights that such a matrix would imply that the symmetric group Sm is a cyclic group, which it is not for m > 2. Various methods and resources were suggested for generating permutation matrices, but ultimately, the conclusion is that no single permutation can achieve the desired cycling effect for larger matrices. The inquiry reflects a broader interest in permutation theory and its limitations. The consensus confirms the non-existence of a solution for m > 2.
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Hello!

I was wondering if there is a way to generate a permutation matrix P such that each application of P to another matrix A will find the "next" permutation of A. I'm looking for a way to generate a permutation matrix P (size m x m) such that applying it m! times to A (m x m) returns A (after having rolled through all possible permutations of A).

Am I looking for something I'm not going to be able to find?

Thanks!
 
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If I understood you correctly you are trying to calculate P^{(m!)}, where P is a permutation matrix. One way I can think of is to use the http://www.ece.cmu.edu/~smart/examples/cycle/cycle.html" , e.g. (4,1,3,2) stands for the matrix

<br /> \begin{bmatrix}<br /> 0 &amp; 0 &amp; 1 &amp; 0 \\<br /> 0 &amp; 0 &amp; 0 &amp; 1 \\<br /> 0 &amp; 1 &amp; 0 &amp; 0 \\<br /> 1 &amp; 0 &amp; 0 &amp; 0 \\<br /> \end{bmatrix}<br /> [/itex]<br /> <br /> (See also <a href="http://en.wikipedia.org/wiki/Permutation_matrix#Examples&quot;" target="_blank" class="link link--external" rel="nofollow ugc noopener">http://en.wikipedia.org/wiki/Permutation_matrix#Examples&quot;</a>)<br /> <br /> Then you have to calculate (4,1,3,2)^(m!) = (4,1,3,2)^(4!). You can use the program http://www.gap-system.org/&quot; and type into the command line: (4,1,3,2)^24 <br /> (see also http://people.math.jussieu.fr/~jmichel/htm/CHAP020.htm&quot; )<br /> <br /> There is a probably a theorem to calculate (a1,a2,...,am)^(m!).
 
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Let me ask it another way...

Is there some permutation that can be done to a list of elements such that the recursive application of that permutation to that list will cycle through all possible permutations?

Basically I'd like something like C++'s next_permutation (but without having each application of the function permute the input list in a different manner than the previous one).

[After experimenting I think I'm looking for something that doesn't exist?]

Thank you to everyone who has replied so far.
 
Indeed, for size m > 2, this does not exist, because it would imply that Sm is a cyclic group (i.e. generated by one element), which it is not for m > 2.
 
Oh phoey!

Thank you Moo of Doom (and the greater whole that is PF).
 
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