Generating function for canonical transformation

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SUMMARY

The discussion focuses on finding the generating function for a canonical transformation defined by the equations Q = p + iaq and P = (p - iaq) / (2ia). The user attempts to express the generating function in terms of F(Q, P) and F(q, p) but struggles with additional terms that complicate the derivation. Ultimately, they determine that the generating function is of the third kind, F_3(Q, p), and derive expressions for q and P in terms of F_3. The final form of the generating function is presented as F_3 = 2Qq + 2pP - (1/2ia)(p^2 + (Q^2/2).

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Homework Statement


Given the transformation

Q = p+iaq, P = \frac{p-iaq}{2ia}


Homework Equations


find the generating function


The Attempt at a Solution



As far as I know, one needs to find two independent variables and try to solve. I couldn't find such to variables.

I've tried expressing it in terms of F(Q,P), and F(q,p) but always had one more term in the equation that prevented me from getting to H(q,p) = -H(Q,P) + \frac{\partial F}{\partial t}

I'm pretty clueless as to what is needed here. Can someone help me get started?

Thanks.
 
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Ok, this is what I did :

Q = 2ia(P + 2q) , P = \frac{p-iaq}{2ia}
which means that Q and p are independent coordintes, which means the generating function will be of the third kind, F_3(Q,p).

for the third kind,
q = -\frac{\partial F_3}{\partial p} = \frac{p}{ia}-2P
P = -\frac{\partial F_3}{\partial Q} = \frac{Q}{2ia}-2q

from the first equation we get
F_3 = 2pP - \frac{p^2}{2ia} + F(Q)
and from the second
F_3 = 2Qq - \frac{Q^2}{4ia} + F(p)

summing both I get
F_3 = 2Qq + 2pP - \frac{1}{2ia} (p^2 + \frac{Q^2}{2})

Does this seem right??
 
Last edited:

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