geometric algebra cross product(adsbygoogle = window.adsbygoogle || []).push({});

--------------------------------------------------------------------------------

The problem statement, all variables and given/known data[/b]

my text (Geometric Algebra for Physicists, by Doran and Lasenby), p. 69, deals with rotating frame {fsubk} (I assume in 3D)

d/dt (fsubk) = omega X fsubk omega being angular velocity

then

omega X fsubk = (-I omega) dot fsubk = fsubk dot (I omega), where I is pseudoscalar and (I omega) is I think the geometric product of I and omega.

I don't understand these algebraic steps. Can someone explain?

I did follow earlier explanations of why with vectors a,b that a X b = -I(a wedge b)

If I have posted this to the wrong forum, would the moderators kindly forward it to a more appropriate one?

Thank you all very much!

Ken Cohen

**Physics Forums - The Fusion of Science and Community**

Join Physics Forums Today!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

# Geometric algebra cross product

Loading...

Similar Threads - Geometric algebra cross | Date |
---|---|

I Geometric intuition of a rank formula | Feb 8, 2018 |

I Is there a geometric interpretation of orthogonal functions? | Jan 25, 2018 |

I Outer product in geometric algebra | Jul 30, 2017 |

I A new vector-product for geometric algebra? | Mar 15, 2017 |

A Hodge Dual as Sequence of Grade Reducing Steps | Aug 2, 2016 |

**Physics Forums - The Fusion of Science and Community**