Geometric Optics- Two Questions

AI Thread Summary
To determine the magnification of a 5 cm object placed 20 cm in front of a lens with a power of -2.5 diopters, the thin-lens equation is applied, revealing that the image distance leads to a magnification of 2/3. The extraneous information about the object's height is noted as unnecessary for this calculation. For the second question regarding lateral displacement in a rectangular piece of crown glass with an angle of incidence of 30 degrees, the angle of refraction is found using Snell's law, followed by trigonometric calculations to determine displacement. The steps involve drawing the ray diagram and applying the appropriate formulas for refraction and displacement. Overall, these calculations illustrate the principles of geometric optics effectively.
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1.Determine the magnification of a 5cm object that has been placed 20 cm in front of a lens with a power of -2.5 d?

2. Light strikes a rectangular piece of crown glass with an angle of incidence of 30 degrees. If the block of glass is 10cm, determine the measure of lateral displacement.

Can anyone give me the steps to solving these? I'm kind of having a hard time.:cry:

It would really be appreciated.:shy:
 
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1. use the thin-lens equation to find the image distance, then use the magnification equation to determine the magnification. The "5 cm" is extraneous information.

2. Draw the ray as it refracts through the glass. Find the angle of refraction. Do a little trig.
 
p=-2.5d
f=-1/2.5=-0.4
i/f=i/v-i/u
-2.5=1/v-(-1/(20/100))
-2.5=1/v+5
1/v=-7.5
m=v/u
(1/-7.5)/(-20/100)
(1/-7.5)*-5
2/3
thus, it is a concave lens
 
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