Given a wave function at t=0, how do you find the wave function at time t?

Click For Summary
SUMMARY

The discussion focuses on determining the wave function \(\psi(r,t)\) at time \(t\) given the initial wave function \(\psi(r,0)=4\pi ij_{1}(kr)(3/\sqrt{34}Y^{0}_{1}+5/\sqrt{34}Y^{-1}_{1})\). Participants suggest applying the time-independent Schrödinger equation (TISE) to find the energy of the state, followed by incorporating the time-dependent Schrödinger equation (TDSE) factor \(e^{-i\omega t}\). If the state is a linear combination of energy eigenstates, each term must be multiplied by the corresponding phase factor, complicating the summation for a closed formula.

PREREQUISITES
  • Understanding of wave functions in quantum mechanics
  • Familiarity with the time-independent Schrödinger equation (TISE)
  • Knowledge of the time-dependent Schrödinger equation (TDSE)
  • Basic concepts of energy eigenstates and their properties
NEXT STEPS
  • Study the application of the time-independent Schrödinger equation (TISE) in quantum systems
  • Learn about the time-dependent Schrödinger equation (TDSE) and its implications for wave functions
  • Explore the concept of energy eigenstates and their role in quantum mechanics
  • Investigate methods for summing series in quantum mechanics for complex wave functions
USEFUL FOR

Quantum physicists, students studying quantum mechanics, and researchers interested in wave function propagation and energy state analysis.

Demon117
Messages
162
Reaction score
1
I am given the following:

A spherically propagating shell contains N neutrons, which are all in the sate

[tex]\psi[/tex](r,0)=4[tex]\pi[/tex]i[tex]j_{1}[/tex](kr)(3/[tex]\sqrt{34}[/tex][tex]Y^{0}_{1}[/tex]+5/[tex]\sqrt{34}[/tex][tex]Y^{-1}_{1}[/tex])

at t = 0.

How do we find [tex]\psi[/tex](r,t)?

My attempt:

I have a few thoughts; could you apply the time-independent Schrödinger equation to find the energy of the state? If that is the case then you would simply tack on the factor of [tex]e^{-i\omega*t}[/tex]. Then you would know that [tex]\hbar*\omega[/tex]=E. . . . right?
 
Physics news on Phys.org
I think that should do it. With the TISE, and the TDSE factor, I think you can it.
 
This will do if your state is energy eigenstate. If it is a linear combination of energy eigenstates, then you will have to multiply each term by the appropriate phase factor. In this case summation of the new series to get a closed formula may not be easy.
 

Similar threads

  • · Replies 3 ·
Replies
3
Views
2K
Replies
7
Views
2K
  • · Replies 3 ·
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 4 ·
Replies
4
Views
3K
Replies
9
Views
3K
  • · Replies 5 ·
Replies
5
Views
2K
  • · Replies 7 ·
Replies
7
Views
3K